((25-4a^2)/(3a))*((24x-6x^2)/(2a^2-3a-20))

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Solution for ((25-4a^2)/(3a))*((24x-6x^2)/(2a^2-3a-20)) equation: 


D( x )

2*a^2-(3*a)-20 = 0

3*a = 0

2*a^2-(3*a)-20 = 0

2*a^2-(3*a)-20 = 0

2*a^2-3*a-20 = 0

2*a^2-3*a-20 = 0

x należy do R

3*a = 0

3*a = 0

3*a = 0

x należy do R

x belongs to the empty set

((25-(4*a^2))/(3*a))*((24*x-(6*x^2))/(2*a^2-(3*a)-20)) = 0

x belongs to the empty set

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